**This post answers the question “How do you calculate capacitors in series and parallel?”. **

Let’s consider first the series combinaton of two capacitors like on the figure below.

The charge these two capacitors are storing is $q\left(t\right)={C}_{1}{v}_{1}\left(t\right)={C}_{2}{v}_{2}\left(t\right)$. At the same time $v\left(t\right)={v}_{1}\left(t\right)+{v}_{2}\left(t\right)$, then $\frac{1}{C}=\frac{1}{{C}_{1}}+\frac{1}{{C}_{2}}$ or $C=\frac{{C}_{1}{C}_{2}}{{C}_{1}+{C}_{2}}$.

For the parallel connection of capacitors like on the figure below, we can conclude that ${q}_{1}={C}_{1}v\left(t\right)$ and ${q}_{2}={C}_{2}v\left(t\right)$.

Then $v\left(t\right)=\frac{{q}_{1}\left(t\right)}{{C}_{1}},v\left(t\right)=\frac{{q}_{2}\left(t\right)}{{C}_{2}}$. And $q\left(t\right)={q}_{1}\left(t\right)+{q}_{2}\left(t\right)$. Then $C={C}_{1}+{C}_{2}$.

More educational content can be found at Reddit community **r/ElectronicsEasy.**