Power Electronics

# Line-commutated three-phase rectifier This post answers the question: “What is line-commutated three-phase rectifier?”. As we know from previous post, these rectifiers are used to convert a fixed voltage, fixed frequency AC power supply into variable DC output. Input signal supply usually characterised by fixed RMS voltage and fixed frequency. Phase controlled thyristors in the rectifier are used to create controlled output (load) voltage and current. This is due to variable delay angle $\alpha$ that can be controlled by gate current of thyristor. Line-commutated three-phase rectifier circuit is depicted on the scheme below. Here three-phase input voltage is supplied through  the star connected transformer. Thyristors are in ON state when they are experiencing positive half-cycle of an input supply voltage. When the input voltage half-cycle is negative, the thyristors are in OFF state. The combination of three thyristors are here have common cathode configuration to control load voltage. Load voltage control can be made by applying positive anode-cathode voltage and gate current with the firing angle $\omega t=\alpha$. In practice, due to commutation problems, the range of firing angle is $0<\alpha <180$. In controlled rectifiers usually natural commutation prociple is used.

Here when thyristor ${T}_{1}$ is ON ($\omega t=\frac{\pi }{6}+\alpha$), voltage across the first winding is ${v}_{1}$. When the thyristor ${T}_{2}$ is ON state ($\omega t=\frac{5\pi }{6}$), thyristor ${T}_{1}$ goes reverse-biased or OFF state, voltage across the second winding is ${v}_{2}$. When thyristor ${T}_{3}$ is ON state ($\omega t=\frac{3\pi }{2}+\alpha$), thyristor ${T}_{2}$ becomes reverse-biased and goes OFF state, so voltage across third winding is ${v}_{3}$.

DC current and voltage  forms for three-phase controlled rectifier are depicted below. The load voltage is ${V}_{D}=\frac{{V}_{m}}{\frac{2\mathrm{\pi }}{3}}{\int }_{\alpha –\frac{\pi }{3}}^{\alpha +\frac{\pi }{3}}\mathrm{cos}\omega td\left(\omega t\right)=\frac{3\sqrt{3}}{2\pi }{V}_{m}\mathrm{cos}\alpha$. For this equation can be seen that if $\alpha <90,$ then load voltage is positive, when $\alpha >90$ the load voltage becomes negative (the rectifier work as an invertor).